Y=-1.75x^2+19.25x

Solution for Y=-1.75x^2+19.25x equation:

=-1.75Y^2+19.25Y

We move all terms to the left:

-(-1.75Y^2+19.25Y)=0

We get rid of parentheses

1.75Y^2-19.25Y=0

a = 1.75; b = -19.25; c = 0;
Δ = b2-4ac
Δ = -19.252-4·1.75·0
Δ = 370.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19.25)-\sqrt{370.5625}}{2*1.75}=\frac{19.25-\sqrt{370.5625}}{3.5}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19.25)+\sqrt{370.5625}}{2*1.75}=\frac{19.25+\sqrt{370.5625}}{3.5}
$